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Este Cmap, tiene información relacionada con: aristotelesen algoritmoa, r = s⋅ t ondorioz a = bq + r = ptq+st=t(pq+s), b = b1⋅ d beraz r= a1⋅d-b1⋅d⋅q =d⋅(a1-b1⋅q), t|b beraz t|zkh(a,b), t|zkh(a,b) eta ondorioz t|d, d|b beraz b = b1⋅ d, d|r beraz d|t, b = p⋅ t ondorioz a = bq + r = ptq+st=t(pq+s), d|b beraz d|t, zkh(b,r)=t beraz d|t, a = bq + r → r = a - bq beraz r= a1⋅d-b1⋅d⋅q =d⋅(a1-b1⋅q), a,b non r, a,b non a,b zenbaki arruntak diren, t|r beraz r = s⋅ t, t|d azken ondorioa t=d, a = a1⋅ d beraz r= a1⋅d-b1⋅d⋅q =d⋅(a1-b1⋅q), t|b beraz b = p⋅ t, a = bq + r = ptq+st=t(pq+s) beraz t|a, d|t azken ondorioa t=d, r zera den (a÷b) zatiketaren hondarra, t|a beraz t|zkh(a,b)